(3x+2)(2x-1)
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(3x+2)(2x-1)(3x+2)(2x-1)(3x+2)(2x-1)两边除以6(x+2/3)(x-1/2)上下除以2^xf(x)=2^(-4)/(2^x+8/2^x)2^x>0所以2^x+8/2^
(3x+2)(2x-1)
(3x+2)(2x-1)
(3x+2)(2x-1)
两边除以6
(x+2/3)(x-1/2)
上下除以2^x
f(x)=2^(-4)/(2^x+8/2^x)
2^x>0
所以 2^x+8/2^x≥2√(2^x*8/2^x)=4√2
所以0<1/(2^x+8/2^x)≤1/4√2=√2/8
所以0
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