:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 10:06:18
:x^2+y^2-xy+x-1/2y+1/4=0求X,Y的值:x^2+y^2-xy+x-1/2y+1/4=0求X,Y的值:x^2+y^2-xy+x-1/2y+1/4=0求X,Y的值两边乘以2,得:2x
:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
:x^2+y^2-xy+x-1/2y+1/4=0 求X,Y的值
两边乘以2,得:
2x²+2y²-2xy+x+y+(1/2)=0
(x²-2xy+y²)+[x²+x+(1/4)]+[y²+y+(1/4)]=0
(x-y)²+[x+(1/2)]²+[y+(1/2)]²=0
则:
x=-1/2
y=-1/2
【原题的符号可能还有问题,给出的解答已经更新了符号】
x^2+y^2-xy+x-1/2y+1/4=0
通分同乘4,得:
[4x²+4y²-4xy+4x-2y+1]/4=0
对分子而言:(4x²-4xy+y²)+2(2x-y)+1+3y²=0
(2x-y)²+2(2x-y)+1+3y²=0
(2x-y+1)²+3y²=0
全部展开
x^2+y^2-xy+x-1/2y+1/4=0
通分同乘4,得:
[4x²+4y²-4xy+4x-2y+1]/4=0
对分子而言:(4x²-4xy+y²)+2(2x-y)+1+3y²=0
(2x-y)²+2(2x-y)+1+3y²=0
(2x-y+1)²+3y²=0
则:
x=-1/2
y=0
楼主是铁一(番禺)的学生???希望帮到你~~
收起
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x+y)(x+y+2xy)+(xy+1)(xy-1)(x+y)(x-y)+4(y-1)
1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y)
{(x-y/x^2-2xy+y^2)-(xy+y^2/x^2-y^2)}*(xy/y-1)
(x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简
因式分解x^2y^2+x^2y+xy^2+3xy+x+y+1
若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思,是3x-2xy-3y/x-2xy-y
计算3xy[2xy-x(y-2)+x-1]
xy-x-y+1/y²-2y+1
y平方-2y+1分之xy-x-y-1
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
[(x+y)^2-(x-y)^2]÷(1/2xy)
1.(xy-1)^2-(x+y-2xy)(2-x-y)2.(x+y)(x+y+2xy)+(xy-1)(xy+1)
(x/y)^2乘以(xy)^-2除以(x^-1y)
因式分解 x(x-1)+y(y+1)-2xy
因式分解:X(X-1)+Y(Y+1)-2XY
x-y/x^2+xy除以xy-x^2/x^2y^2-x^4*1/x-y
(x+y)(x-1)-xy-y^2 怎么因式分解?