若sinα+conα=7/13(0＜x＜π),则tanα=若sinα+conα=7/13(0＜x＜π),则tanα=若sinα+conα=7/13(0＜x＜π),则tanα=

若sinα+conα=7/13(0＜x＜π),则tanα=若sinα+conα=7/13(0＜x＜π),则tanα=若sinα+conα=7/13(0＜x＜π),则tanα=
若sinα+conα=7/13(0＜x＜π),则tanα=
若sinα+conα=7/13(0＜x＜π),则tanα=
若sinα+conα=7/13(0＜x＜π),则tanα=

若sinα+conα=7/13(0＜x＜π),则tanα=若sinα+conα=7/13(0＜x＜π),则tanα=若sinα+conα=7/13(0＜x＜π),则tanα=
sina+cosa=7/13
√2(cos45°sina+sin45°cosa)=√2sin(45°+a)
=7/13
sin(45°+a)=7√2/26

令tan(α/2)=t,因为0＜x＜π,所以0＜α/2＜π/2,所以t>0,则有sinα=2t/(1+t^2),cosα=(1-t^2)/(1+t^2),所以sinα+conα=(2t+1-t^2)/(1+t^2)=7/13,解之得:t=3/2或t=-1/5(由前面理由,舍去!),所以t=3/2,又tanα=2t/(1-t^2)代入t=3/2,得tanα=-12/5.