∫[x+e^(arctanx)/ (1+x^2) ]dx=

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/07 16:24:43
∫[x+e^(arctanx)/(1+x^2)]dx=∫[x+e^(arctanx)/(1+x^2)]dx=∫[x+e^(arctanx)/(1+x^2)]dx=

∫[x+e^(arctanx)/ (1+x^2) ]dx=
∫[x+e^(arctanx)/ (1+x^2) ]dx=

∫[x+e^(arctanx)/ (1+x^2) ]dx=