已知根号（lg(11/2-9cos(x+π))）≤1 的值域

已知根号（lg(11/2-9cos(x+π))）≤1 的值域
已知根号（lg(11/2-9cos(x+π))）≤1 的值域

已知根号（lg(11/2-9cos(x+π))）≤1 的值域
0<=√lg(11/2+9cosx)<=1
0<=lg(11/2+9cosx)<=1
1<=11/2+9cosx<=10
-9/2<=9cosx<=9/2
-1/2<=cosx<=1/2
所以2kπ-2π/3≤2kπ-π/3,2kπ+π/3≤2kπ+2π/3

(x-y-6)a=y-2x+4
则x-y-6=y-2x+4=0时成立
所以x=-2，y=-8
所以直线过A(-2,-8)
所以最大距离就是AP=10
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