若实数x>0,y>0,满足x+2y=1,则xy最大值是?用基本不等式解.急

若实数x,y满足x-y+1》=0,x+y>=0,x 若实数x,y满足x-y+1>=0,x+y>=0,x 若实数x,y满足不等式组x>=0 ,y>=0,x+2y 若实数x,y满足x^2-xy-y^2 =0,则x/y=? 已知实数x,y满足x-ay-1>=0,2x+y>=0,x 若实数X,Y满足X²+Y²+4X-2Y +1=0,则X²-6X+Y²-2Y的最大值是多少 实数x,y满足{x-y+1>=0;y+1>=0;x+y+1 若实数x,y满足x²+y²-2x+4y=0,求x-y的最大值 若实数x y满足（x+y)²+（x+y)-2=0则x+y值为 已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y 若实数xy满足（x+y+2)(x+y-1)=0,则x+y的值是 若实数x,y满足约束条件x-y-2=0,2y-3 设实数x,y满足 x>=0 x-2y>=0 x-y-2 当实数x,y,满足约束条件{x>0 y>=x 2x+y+k 若实数X,Y满足{ x-y-1≤0,x+y-3≤0,x≥1,则函数z=2x-y的最大值 若实数x,y满足x^2+y^2-4x-2y+5=0,则x+y/2x-1 若实数x满足条件x>=0,y 已知实数x,y满足 2x+y-2>=0,x-2y+k>=0,x-1