1/(2/3)/(3/4)/.../（4011/4012）=急

来源：学生作业帮助网编辑：六六作业网时间：2024/07/06 19:26:23

1/(2/3)/(3/4)/.../（4011/4012）=急1/(2/3)/(3/4)/.../（4011/4012）=急1/(2/3)/(3/4)/.../（4011/4012）=急=1×3/2×

1/(2/3)/(3/4)/.../（4011/4012）=急
1/(2/3)/(3/4)/.../（4011/4012）=
急

1/(2/3)/(3/4)/.../（4011/4012）=急
=1×3/2×4/3×……×4012/4011
约分
=1/2×4012
=2006

=1*(3/2)*(4/3)*...*(4012/4011)=2006

1 2 3 4 1 2 3 4 1 2 3 4 1,2,3,4, 1 2 3 4 1 2 3 4 1,2,3,4, 1,2,3,4, 1,2,3,4, 1,2,3,4, 1 2 3 4 1,2,3,4, 1,2,3,4, 1,2,3,4, 1、2、3、4 1+2+3×4 1,2,3,4 1+2+3+4+.