1、What is the maximum number of cubes with sides of a length that could fit inside a cube with sides of length 2s?(A) 8 (B) 16 (C) 32 (D) 64 (E) 128可是不知道怎么算出来的2、The sum of the lengths of two sides of isosceles triangle K is
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/23 03:40:57
1、What is the maximum number of cubes with sides of a length that could fit inside a cube with sides of length 2s?(A) 8 (B) 16 (C) 32 (D) 64 (E) 128可是不知道怎么算出来的2、The sum of the lengths of two sides of isosceles triangle K is
1、What is the maximum number of cubes with sides of a length that could fit inside a cube with sides of length 2s?
(A) 8 (B) 16 (C) 32 (D) 64 (E) 128
可是不知道怎么算出来的
2、The sum of the lengths of two sides of isosceles triangle K is 7.K has a side of length 4.
比大小：The perimeter of K和 11
这道题我知道要分类讨论,算出来两个结果周长都等于11,那为什么不能选“=”而要选“信息不足,无法比较”?
3、
The 20 people at party are divided into N mutually exclusive groups in such a way that the number of people in any group does not exceed the number in any other group by more than 1.
比大小：The value of nif ) at least one of the groups consists of 3 people和6
1、What is the maximum number of cubes with sides of a length that could fit inside a cube with sides of length 2s?(A) 8 (B) 16 (C) 32 (D) 64 (E) 128可是不知道怎么算出来的2、The sum of the lengths of two sides of isosceles triangle K is
边长为2s的立方体,其体积为8s三次方,设有x个小立方体其边长为a,此时若要完全填满则有x*a3=8S3,即x=(2S/a)3,所以x只能为64.等腰三角形两边和是7,其中一边为4,则三角形三遍距离组成可能为3,3,4；4,4,3；3.5,3.5,4,所以周长可以为10或11.第三题那个是分开的,A选项应该是the value of n if at least one of the groups consists of 3 people.这时候由题意可知,20人分组情况为6个3人组,1个2人组,或者4个3人组,4个2人组,或者2个3人组,7个2人组,或者4个3人组,和2个4人组,n可以取7,8,9,6所以无法确定
无法确定 。