已知x-3y=3,则7+6y-2x=
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已知x-3y=3,则7+6y-2x=已知x-3y=3,则7+6y-2x=已知x-3y=3,则7+6y-2x=∵x-3y=3∴x=3+3y代入7+6y-2x得=7+6y-2·(3+3y)=7+6y-6-
已知x-3y=3,则7+6y-2x=
已知x-3y=3,则7+6y-2x=
已知x-3y=3,则7+6y-2x=
∵x-3y=3
∴x=3+3y
代入7+6y-2x 得
=7+6y-2·(3+3y)
=7+6y-6-6y
=1
原式=7-2(x-3y)
=7-2×3
=1
x-3y=3
2x-6y=6
6y-2x=-6
7+(-6)=1
由x-3y=3得3y-x=-3
7+6y-2x=7+2(3y-x)
=7+2*(-3)
=1
很简单,答案 1
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