2x^3-18x=0 2x^3-18x=0

一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X x+(x+3)+2x+(2x-18)=255 x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 X^3-7X^2+18X-24=0 x^2-3x-18=0 求x matlab中a(x)=x^4+3x^3+9x-18 b(x)=x^5-4x^3-18x+7 c(x)=x^7+6x^5+9x^3-5x^2-2 d(x)=x^9-8x^7+6x^5-4x^4+d(x)=x^9-8x^7+6x^5-4x^4+6x^2+3 求e(x)=a(x)*b(x)*c(x)*d(x) 解方程 式子 6-2x+3x=3x-4x+3x+18 6-x+3x=2x-5x+1 2x-1=5x-36-2x+3x=3x-4x+3x+18 6-x+3x=2x-5x+12x-1=5x-3 已知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)= 已知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)= 已知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)= 知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)= 已知集合A={x/ x^2+3x-18>0},B={x/ (x-k)(x-k-1)= 若x^2-8x+13=0求(x^4-6x^3-2x^2+18x+23) x²-3x-18＜0 （x-1)(x+2)=(x-2)(2x+1) 已知 X=4- 根号3 求 (X*X*X*X-6X*X*X-2X*X+18X+23) / (X*X-8X+15)的值紧急,,明天有用,, 已知集合A={x|x^2 +3x-18>0},B={x|(x-k)(x-k-1) 1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2x+18 1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2x+18