已知实数a,b满足a(a+1)-(a²+2b）=1,求a²-4ab+4b²-2a+4b的值

已知实数a,b满足a(a+1)-(a²+2b）=1,求a²-4ab+4b²-2a+4b的值
已知实数a,b满足a(a+1)-(a²+2b）=1,求a²-4ab+4b²-2a+4b的值

已知实数a,b满足a(a+1)-(a²+2b）=1,求a²-4ab+4b²-2a+4b的值
a(a+1)-(a²+2b）=1
a²+a-a²-2b=1
a-2b=1
a²-4ab+4b²-2a+4b
=(a-2b)²-2(a-2b)
=(a-2b)(a-2b-2)
=1×(1-2)
=-1