化简 2^(x+1)/2^(1-x) [(2a)^-1b^3]^2 2^5/2 化简2^(x+1)/2^(1-x)[(2a)^-1b^3]^2 2^5/2

化简 2^(x+1)/2^(1-x) [(2a)^-1b^3]^2 2^5/2 化简2^(x+1)/2^(1-x)[(2a)^-1b^3]^2 2^5/2
化简 2^(x+1)/2^(1-x) [(2a)^-1b^3]^2 2^5/2
化简
2^(x+1)/2^(1-x)
[(2a)^-1b^3]^2
2^5/2

化简 2^(x+1)/2^(1-x) [(2a)^-1b^3]^2 2^5/2 化简2^(x+1)/2^(1-x)[(2a)^-1b^3]^2 2^5/2
(1)2^(x+1)/2^(1-x)=2^[(x+1)-(x-1)]=2^2=4
(2) [(2a)^-1b^3]^2=b^6/(4a^2)
(3) 2^5/2 =2^(5-1)=2^4=16

2^(x+1)/2^(1-x)
=2^（x+1-1+x）=2^（2x)

2^(x+1)/2^(1-x)
=2^[(x+1)-(1-x)]
=2^(2x)
[(2a)^-1b^3]^2
=(2a)^(-2)×b^6
2^5/2
=2^(5-1)
=2^4

2^(x+1)/2^(1-x)=2^(x+1-(1-x))=2^(2x)=4^x;
[(2a)^-1b^3]^2 =(a^-1)(b^6)/2;
2^5/2=2^(5-1)=2^4=16

1、都是2的指数，所以直接计算指数：(x+1)-(1-x)=2x ,所以得到：2^(2x)=4^x
2、指数2乘以括号内各项的指数，最后化简为：b^6/(2a)^2=b^6/4a^2
3、2^4 =16