求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/09 04:57:15
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)求值sin10π/3-根号2cos(-19π/4)+ta
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
求值sin10π/3-根号2cos(-19π/4)+tan(13π/3)
sin10π/3-根号2cos(-19π/4)+tan(13π/3)
=-sinπ/3-√2cos(3π/4)+tan(π/3)
=-√3/2+1+√3
=1-(√3/2)