y=(x+(1+x^2)^1/2)^1/3+(x-(1+x^2)^1/2)^1/3的反函数
来源:学生作业帮助网 编辑:六六作业网 时间:2025/01/31 00:22:56
y=(x+(1+x^2)^1/2)^1/3+(x-(1+x^2)^1/2)^1/3的反函数y=(x+(1+x^2)^1/2)^1/3+(x-(1+x^2)^1/2)^1/3的反函数y=(x+(1+x^
y=(x+(1+x^2)^1/2)^1/3+(x-(1+x^2)^1/2)^1/3的反函数
y=(x+(1+x^2)^1/2)^1/3+(x-(1+x^2)^1/2)^1/3的反函数
y=(x+(1+x^2)^1/2)^1/3+(x-(1+x^2)^1/2)^1/3的反函数
y^3=2x+3y{[x+√(1+x^2)][x-√(1+x^2)]}^(1/3)
=2x-3y,
∴x=(y^3+3y)/2,
x,y互换得y=(x^3+3x)/2,为所求.
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
x+2y=2x+y+1=7x-y 求:2x-y?
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
y=(2x)/x-1化简成用y表示x
二元一次方程 :2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y
(x-y)^2+(x+y)(x-y) 其中 X =3 Y=-1
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
若x*x+y*y=x+y-1/2,求x,y的值如题
函数,y=3x/(x^2+x+1) ,x