(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=
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(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=(2/3a^4b^7-1/9a^2b^6)除以(-1/3
(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=
(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=
(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=
(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2
=(2/3a^4b^7-1/9a^2b^6)÷(1/9a^2b^6)
=6a^2b-1
不懂得欢迎追问.
(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2
=(2/3a^4b^7-1/9a^2b^6)除以1/9a^2b^6
=2/3a^4b^7除以1/9a^2b^6-1/9a^2b^6除以1/9a^2b^6
=6a^2b-1
(a^2+1)(-4a^2+1)+a^4-1 3a(a-b)(a+b)-6(b-a)^2a^2-9(a-b)^2= 3a(a-b)(a+b)-6(b-a)^2=
1/4(a-b)^2+3(a-b)(a+b)+9(a+b)^2
2a-{7b+[4a-7b-(2a-6a-4b)]-3a
等式:(a+b)^0=1 (a+b)^1=a+b (a+b)^2(a+b)^0=1(a+b)^1=a+b(a+b)^2=a^2+2ab+b^2(a+b)^3=a^3+3a^2b+3ab^2+b^3问:(a+b)^4=?(a+b)^5=?``````` (a+b)^9=?
初二分式的加减法2a-b-c/(a-b)(a-c)+ 2b-c-a/(b-c)(b-a)+ 2c-b-a/(c-b)(c-a)3a-6b/a+b- 5a-6b/a-b- 4a-5b/a+b+ 7a-8b/b-a注:有空格的地方是下一个分式
1/a-b-1/a+b-2b/a^2+b^2-4b^3/a^4+b^4+8b^7/b^2-a^2
1/(a-b)-1/(a+b)-(2b)/(a^2+b^2)-(4b^3)/(a^4+b^4)+(8b^7)/(b^8-a^8)快
5(a*a*b-3*a*a*b)-2*(a*a*b-7*a*b*b)
先化简,再求值:(2a-b)^2-(2a+b)(a-b)-3(a-3b)(a+3b),其中|a-1|+b^2=6b-9
(a-2b)(a^2+2ab+4b^2)-a(a+3b)(a-3b),其中a=-1/9,b=1求a,b
因式分解:1、a*a*a*a+2a*a*a*b+3a*a*b*b+2a*b*b*b+b2、(a+1)(a+3)(a+4)(a+6)-280
计算:(-2a^2b)^2-(3a^3b^2)÷5a^2b^2+7a^9b^6÷2a^5b^4
a+2b/2a-3b=3 求解4b+2a/9b-6a-4a-6b/3a+6b=?
当a+2b/2a-3b=3,求代数式4b+2a/9b-6a-4a-6b/3a+6b
a+2b/2a-3b=3 求解4b+2a/9b-6a-4a-6b/3a+6b=?
计算(3a-2b)(9a*a+6ab+4b*b)-(3a+2b)(9a*a-6ab+4b*b)
判断下列各式是否正确:(1)|-a|=|a|.(2)-|a|=|-a|.(3)a分之|a|=|a|分之a.(4)若|a|=|b|,则a=b.(5)若a=b,则|a|=|b|.(6)若|a|>|b|,则a>b.(7)若a>b,则|a|大于|b|.
1/(a-b)-1/(a+b)-2b/(a^2+b^2)-4b^3/a^4+b^4+8b^7/b^8-a^81/(a-b)-1/(a+b)-2b/(a^2+b^2)-4b^3/(a^4+b^4)+8b^7/(b^8-a^8)