设x2+ax+b是xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2的公因式,则1+a+b=()
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设x2+ax+b是xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2的公因式,则1+a+b=()设x2+ax+b是xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2的公因式
设x2+ax+b是xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2的公因式,则1+a+b=()
设x2+ax+b是xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2的公因式,则1+a+b=()
设x2+ax+b是xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2的公因式,则1+a+b=()
xn-x3+5x2+x+1与3xn-3x3+14x2+13x+2存在公因式,即存在一个x值能令两式均能为0,(1)式乘3-(2)式,得x^2-10x+1=0,所以a=-10,b=1,所以a+b+1=-8吧.