求不定积分,被积函数为(sin(x)^2+1)^(1/2)
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/19 22:47:53
求不定积分,被积函数为(sin(x)^2+1)^(1/2)求不定积分,被积函数为(sin(x)^2+1)^(1/2)求不定积分,被积函数为(sin(x)^2+1)^(1/2)(sin(x)^2+1)^
求不定积分,被积函数为(sin(x)^2+1)^(1/2)
求不定积分,被积函数为(sin(x)^2+1)^(1/2)
求不定积分,被积函数为(sin(x)^2+1)^(1/2)
(sin(x)^2+1)^(1/2)
原式=|根号2（sin0.5x2+cos0.5x2）|=根号2|sin（0.5x2+0.25π）|
剩下的应该会了吧~