3[6X + 6(X-1)+ 6(X-2)+……+ 6×1]=9X(X+1)不懂左边是怎么变成右边的.
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3[6X+6(X-1)+6(X-2)+……+6×1]=9X(X+1)不懂左边是怎么变成右边的.3[6X+6(X-1)+6(X-2)+……+6×1]=9X(X+1)不懂左边是怎么变成右边的.3[6X+6
3[6X + 6(X-1)+ 6(X-2)+……+ 6×1]=9X(X+1)不懂左边是怎么变成右边的.
3[6X + 6(X-1)+ 6(X-2)+……+ 6×1]=9X(X+1)
不懂左边是怎么变成右边的.
3[6X + 6(X-1)+ 6(X-2)+……+ 6×1]=9X(X+1)不懂左边是怎么变成右边的.
3[6X + 6(X-1)+ 6(X-2)+……+ 6×1]
=3*6*[X+(X-1)+(X-2)+.+1]
=3*6*[(X+1)*X/2]
=9*X*(X+1)
就是用的个等差数列求和
左边中括号内等差数列求和得3X(X+1)再乘外边的3就好啦
左边=3*6*[x+(x-1)+(x+2)+...+1]=3*6*[x*(x+1)]/2=右边
注:求和公式1+2+3+...+(x-1)+x=(1+x)+[2+(x-1)]+[3+(x-2)]+...=(x+1)*x/2
先把6提出来,左边=18{x+(x-1)+……+1}
an-an-1=-1
所以an为以X为首项,-1为公差的等差数列
{x+(x-1)+……+1}=Sn(各项和)=x(x+1)/2
左边=18{x+(x-1)+……+1}=9X(X+1)
没学数列的话那我就不会证了
3[6X + 6(X-1)+ 6(X-2)+……+ 6×1]
=3*6*[X+(X-1)+(X-2)+......+1]
=3*6*[(X+1)*X/2]
=9*X*(X+1)
这里用了一个公式!!!!!
求和公式1+2+3+...+(x-1)+x=(1+x)+[2+(x-1)]+[3+(x-2)]+...=(x+1)*x/2
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