若|x+y-5|+(xy-6)²=0,则x²+y²的值为多少

若|x+y-5|+(xy-6)²=0,则x²+y²的值为多少
若|x+y-5|+(xy-6)²=0,则x²+y²的值为多少

若|x+y-5|+(xy-6)²=0,则x²+y²的值为多少
因为：|x+y-5|+(xy-6)^2=0,所以：x+y=5,xy=6
所以：x^2+y^2=(x+y)^2-2xy=25-12=13

解；因为|x+y-5|+(xy-6)²=0,
所以x+y-5=0 xy-6=0
所以x1=2.y1=3
或x2=3.y2=2
故x²+y²=13