因式分解:8x²(2x²-y²)+y四次方 (x²+x)²-(x+1)²
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因式分解:8x²(2x²-y²)+y四次方 (x²+x)²-(x+1)²
因式分解:8x²(2x²-y²)+y四次方 (x²+x)²-(x+1)²
因式分解:8x²(2x²-y²)+y四次方 (x²+x)²-(x+1)²
8x²(2x²-y²)+y四次方
=16x的4次方-8x²y²+y的4次方
=(4x²-y²)²
=(2x+y)²(2x-y)²
(x²+x)²-(x+1)²
=(x²+x+x+1)(x²+x-x-1)
=(x+1)²(x²-1)
=(x+1)²(x+1)(x-1)
=(x+1)³(x-1)
如果本题有什么不明白可以追问,
8x²(2x²-y²)+y四次方
=16x^4-8x²y²+y^4
=(4x²-y²)²
=(2x+y)²(2x-y)²;
(x²+x)²-(x+1)²
=(x²+x+x+1)(x²+x-x-1)
=(...
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8x²(2x²-y²)+y四次方
=16x^4-8x²y²+y^4
=(4x²-y²)²
=(2x+y)²(2x-y)²;
(x²+x)²-(x+1)²
=(x²+x+x+1)(x²+x-x-1)
=(x+1)²(x+1)(x-1)
=(x+1)³(x-1)
如果本题有什么不明白可以追问,如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢。
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8x^2(2x^2-y^2)+y^4
=16x^4-8x^2y^2+y^4
=(4x^2-y^2)^2
=(2x+y)^2(2x-y)^2
(x^2+x)^2-(x+1)^2
=x^4+2x^3-2x-1
=(x^2+1)(x^2-1)+2x(x^2-1)
=(x^2-1)(x^2+2x+1)
=(x+1)(x-1)(x+1)^2
=(x+1)^3(x-1)