f(t)=[5sin(8t)]^2 怎样判断是否周期信号?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/07/31 23:40:10
f(t)=[5sin(8t)]^2怎样判断是否周期信号?f(t)=[5sin(8t)]^2怎样判断是否周期信号?f(t)=[5sin(8t)]^2怎样判断是否周期信号?f(t)=[5sin(8t)]^

f(t)=[5sin(8t)]^2 怎样判断是否周期信号?
f(t)=[5sin(8t)]^2 怎样判断是否周期信号?

f(t)=[5sin(8t)]^2 怎样判断是否周期信号?
f(t)=[5sin(8t)]^2=(25/2)[2(sin8t)^2-1]+25/2=-(25/2)cos16t+25/2.
是周期信号,周期是T=2π/16=π/8.