6x^2-xy-2y^2-4x+5y-2因试分解
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6x^2-xy-2y^2-4x+5y-2因试分解6x^2-xy-2y^2-4x+5y-2因试分解6x^2-xy-2y^2-4x+5y-2因试分解原式=（3x-2y）(2x+y)-4x+5y-2(十字相
6x^2-xy-2y^2-4x+5y-2因试分解
6x^2-xy-2y^2-4x+5y-2因试分解
6x^2-xy-2y^2-4x+5y-2因试分解
原式=（3x-2y）(2x+y)-4x+5y-2 (十字相乘)
=(3x-2y+1)(2x+y-2)
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待定系数法结合十字交叉法 望采纳哈
6x^2-xy-2y^2-4x+5y-2
=(2x+y)(3x-2y)-4x+5y-2
下面我们用待定系数法
来解答
(2x+y)(3x-2y)-4x+5y-2=（2x+y+m)(3x-2y+n)
=6x^2-xy-2y^2-(3m+2n)x+(n-2m)y+mn
mn=-2
3m+2n=-4
n-2m=5
n=1
m...
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6x^2-xy-2y^2-4x+5y-2
=(2x+y)(3x-2y)-4x+5y-2
下面我们用待定系数法
来解答
(2x+y)(3x-2y)-4x+5y-2=（2x+y+m)(3x-2y+n)
=6x^2-xy-2y^2-(3m+2n)x+(n-2m)y+mn
mn=-2
3m+2n=-4
n-2m=5
n=1
m=-2
(2x+y)(3x+2y)-4x+5y-2=（2x+y-2)(3x-2y+1)
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