已知x≠y,x2+√2y=√3,y2+√2x=√3,求xy=?

已知x≠y,x2+√2y=√3,y2+√2x=√3,求xy=?
已知x≠y,x2+√2y=√3,y2+√2x=√3,求xy=?

已知x≠y,x2+√2y=√3,y2+√2x=√3,求xy=?
x2+√2y=√3,y2+√2x=√3,
两式相减得x²-y²+√2y-√2x=0
(x+y)(x-y)-√2(x-y)=0
(x-y)(x+y-√2)=0
∴x=y 或x=√2-y
代入x2+√2y=√3即可

两式相乘然后化简得到(xy)2+2xy=3-2√3 自己去解吧