求y=x^2-x+2/2x^2-2x+3的值域
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求y=x^2-x+2/2x^2-2x+3的值域求y=x^2-x+2/2x^2-2x+3的值域求y=x^2-x+2/2x^2-2x+3的值域答:y=(x^2-x+2)/(2x^2-2x+3)=(1/2)
求y=x^2-x+2/2x^2-2x+3的值域
求y=x^2-x+2/2x^2-2x+3的值域
求y=x^2-x+2/2x^2-2x+3的值域
答:
y=(x^2-x+2)/(2x^2-2x+3)
=(1/2)(2x^2-2x+3+1)/(2x^2-2x+3)
=1/2+1/[4(x-1/2)^2+5]
因为:4(x-1/2)^2+5>=0+5=5
所以:0
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