23题,
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23题,23题, 23题,(n+7)^2-(n-5)^2=[(n+7)+(n-5)][(n+7)-(n-5)]=(2n+2)×12=24(n+1)(n+7)^2-(n-5)^2能被24整除
23题,
23题,
23题,
(n+7)^2-(n-5)^2
=[(n+7)+(n-5)][(n+7)-(n-5)]
=(2n+2)×12
=24(n+1)
(n+7)^2-(n-5)^2能被24整除