y=sin(x-π/12)cos(x-π/12)求对称中心和最小正周期

y=sinπx+cosπx的周期 函数y=sin(x)cos(x+ π/4)+cos(x)sin(x+π/4)的最小正周期是 已知sinx=3/5,x∈(π/2,π),求【sin(x+y)+sin(x-y)】/【cos（x+y）+cos（x-y）】的值 y=(sin x + COS x)^2 y=2cos x (sin x+cos x) y=2cos(x/4+ π/3)-3sin(x- π/4)y=sin(4x- π/3)-cos(3x+π/2) 化简:y=2sinxsin(x-π/2)+cos²x-sin²x 求函数y=sin^4x+cos^4x,x(0,π/6)的最小值 1.y=sin(-X+π/6)2.y=cos(-2X+π/3) cos(x-y/2)=-1/9,sin(x/2-y)=2/3,π/2 化简sin (x+y)sin x +cos (x+y)cos x= 函数y=sin(2x+α)cos(x+α)-cos(2x+α)sin(x+α)在x=π/3处的导函数为 y=sinωx+cosωx的一条对称轴是x=-π/12,求ω sin(x+y)sin(x-y)=k,求cos^2x-cos^2y y=cosπx*cos(πx-π/3)+sin^2πx的周期、单调区间、值域 证明COS（X+Y）COS（X-Y）=COS^2X-SIN^2Y 证明cos(x+y)cos(x-y)= cos^2(x)-sin^2(y) 函数Y=sin(2x+π/3)cos(x-π/6)-cos(2x+π/3)sin(x-π/6)的图像的一条对称轴方程是多少