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32··········32··········32··········由于是无色溶液,所以其中肯定没有CuCl2（蓝色）加入了BaCl2有沉淀,再加入HNO3完全溶解,说明沉淀只有BaCO3,所以肯

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由于是无色溶液,所以其中肯定没有CuCl2（蓝色）
加入了BaCl2有沉淀,再加入HNO3完全溶解,说明沉淀只有BaCO3,所以肯定没有Na2SO4(BaSO4不溶解在酸中)
A,所以是BaCO3；D,是BaCO3与HNO3反应所得,为CO2
(2)所以不含有Na2SO4,CuCl2
（3）因为固体中一定有Na2CO3
所以Na2CO3+BaCl2===BaCO3(沉淀)+2NaCl
所以一定有NaCl.而可能有KNO3（不与BaCl2反应的,所以保持原来状态）
（4）KNO3与NaCl,只能通过焰色反应区别是否有K+和Na+

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