(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)+㏒2(1+根下2+根下3)+㏒2(1+根下2-根下3)-㏒23㏒34
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(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)+㏒2(1+根下2+根下3)+㏒2(1+根下2-根下3)-㏒23㏒34(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)+㏒2
(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)+㏒2(1+根下2+根下3)+㏒2(1+根下2-根下3)-㏒23㏒34
(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)+㏒2(1+根下2+根下3)+㏒2(1+根下2-根下3)-㏒23㏒34
(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)+㏒2(1+根下2+根下3)+㏒2(1+根下2-根下3)-㏒23㏒34
原式=(2lg2+lg3)/(lg10+lg0.6+lg2)+log2(1+2+2√2-3)-lg3/lg2*2lg2/lg3
=lg(4*3)/lg(10*0.6*2)+log2(2√2)-2
=1+3/2-2
=1/2
计算 (2lg2+lg3)/(1+lg0.6+lg2)
lg0.5/lg0.9怎么化为-lg2/2lg3-1,要详细哦,跪求,对数
(2lg2+lg3)/[1+(1/2)lg0.36+(1/3)lg8]等于什么
求1+1/2lg0.36+1/3lg8分之2lg2+lg3的值
2lg2+lg3除以1+1/2lg0.36+1/3lg8等于多少?
(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)
计算2lg2+lg3/1+1/2lg0.36+1/4lg
计算2lg2+lg3/1+1/2lg0.36+lg8如题
计算(2lg2+lg3)/(1+0.5lg0.36+1/3lg8)郁闷.
2lg2+lg3除以2+lg0.36+2lg2
(2lg2+lg3 ) / (2+ lg0.36+2 lg2)
计算(2lg2+lg3)/(2+lg0.36+2/3lg8)
求 2lg2+lg3 除 1+1/2lg0.36+1/3lg8 的值有会的没?
(2lg2+lg3)/[1+(1/2)lg0.36+(1/3)lg8]需要一点小小的过程
计算[(lg2+2lg3)/(2+lg0.9+lg0.2)]^3-4^6×2^(-13)
计算下列公式 (1)(2lg2+lg3)/(1+1/2lg0.36+1/3lg8) (2) lg5^2+2/3lg8+lg5*lg20+(lg2)^2
log2√5/56+log^14-1/2log2^35 (2lg2+lg3)/(2+lg0.36+2lg2) √是根号,5/56全在根号下
高一数学,麻烦大家了2lg2+lg3--------------------的值1+0.5lg0.36+(1/3)lg82lg2+lg3------------------------------的值1+0.5lg0.36+(1/3)lg8 -------是分数线哈,呵呵,打不出来。。。