cos(2x+π/3)+sin^2x-1/2 求x在 0到π之间时,函数单调递减区间

化简 1/2cos x-根号3/2sin x 根3sin x+cos x 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x 2cos x (sin x -cos x)+1 (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x (sin x*sin 3x)sin^2 x+（cos x*cos 3x)cos^2 x 如何变到1/2[(cos 2x-cos4x)sin^2x+(cos2x+cos4x)cos^2x] 已知sin(x)+3cos(x)=2,求sin(x)-cos(x)/sin(x)+cos(x)=? sin[cos^2(x^3+x)],求导 化简（1)√3sin x+cos x (2）√2(sin x-cos x) （3）√2cos x-√6sin x 求证(3-sin^4 x-cos^4 x)/2cos^2 x=1+tan^2 x+sin^2 x 2sin^2x - 5sin x cos x=3 cos^2x,求X, Sin x-sin y=2/3 cos x-cos y=1/2 求cos(x-y) sin(x+1/2π)=cosx?还是cos-x 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). 化简 1/2cos x-根号3/2sin x