设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)

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设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)设集合A=｛x/(x+3)(2-

设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)
设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)

设集合A=｛x/(x+3)(2-x)｝＞=0,B=｛x/x^-4ax-(1-4a^)
x/(x+3)(2-x)>=0 =>
1.x>0 and (x>-3 and x0

没看明白 b是啥啊