设z=㏑√(x²+y²)求（dz/dx）²+(dy/dx)²

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设z=㏑√(x²+y²)求（dz/dx）²+(dy/dx)²设z=㏑√(x²+y²)求（dz/dx）²+(dy/dx)²

设z=㏑√(x²+y²)求（dz/dx）²+(dy/dx)²
设z=㏑√(x²+y²)求（dz/dx）²+(dy/dx)²

设z=㏑√(x²+y²)求（dz/dx）²+(dy/dx)²
z=0.5㏑(x²+y²)
dz/dx =x/(x²+y²)
dy/dx=y/(x²+y²)
所以（dz/dx）²+(dy/dx)²=1/(x²+y²)