设函数f (x)=√3cos^2wx+sinwxcoswx+a（其中w＞0,α∈R）且f（x）的图像在y轴右侧的第一个最高点的横坐标为π/6.(1)求w的值.(2)如果f(x)在区间[-π/3,5π/6]上的最小值为根号3,求a的值急用,

设x∈R,函数f(x)=cos(wx+f)(w>0,-π/2 已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0 已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0 已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 老师好：设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+g)+cos(wx+g) (w>0,|g| 设函数f(x)=sin(wx+q)+cos(wx+q)(w>0,q的绝对值 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0 已知函数为f(x)=√3sin(wx+φ)-cos(wx+φ)（w>0,0 设x∈R,函数f(x)=cos^2(wx+p)-1/2(w>0,0 [非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0