y=(7x-3)/(4x+2)的值域

来源：学生作业帮助网编辑：六六作业网时间：2024/11/08 23:02:55

y=(7x-3)/(4x+2)的值域y=(7x-3)/(4x+2)的值域y=(7x-3)/(4x+2)的值域y=(7x-3)/(4x+2)=[(7/4)(4x+2)-13/2]/(4x+2)=7/4-

y=(7x-3)/(4x+2)的值域
y=(7x-3)/(4x+2)的值域

y=(7x-3)/(4x+2)的值域
y=(7x-3)/(4x+2)
=[(7/4)(4x+2)-13/2]/(4x+2)
=7/4- (13/2)/(4x+2)
∵ 4x+2≠0
∴ y=7/4- (13/2)/(4x+2)≠7/4
即函数y=(7x-3)/(4x+2)的值域{y|y≠7/4}