(1)已知(x-y+3)^2+√2-y=0,试求x+y的值(2)计算:(a+3)(a-1)+a(a-2)

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(1)已知(x-y+3)^2+√2-y=0,试求x+y的值(2)计算:(a+3)(a-1)+a(a-2)(1)已知(x-y+3)^2+√2-y=0,试求x+y的值(2)计算:(a+3)(a-1)+a(

(1)已知(x-y+3)^2+√2-y=0,试求x+y的值(2)计算:(a+3)(a-1)+a(a-2)
(1)已知(x-y+3)^2+√2-y=0,试求x+y的值
(2)计算:(a+3)(a-1)+a(a-2)

(1)已知(x-y+3)^2+√2-y=0,试求x+y的值(2)计算:(a+3)(a-1)+a(a-2)
1,(x-y+3)^2>=0,√2-y>=0,所以只有(x-y+3)^2=0,√2-y=0
于是x-y+3=0,2-y=0,解得y=2,x=-1
x+y=1;
2,展开得a^2+2a-3+a^2-2a=2a^2-3

(1) -3+√2
(2)2a²-3

(x-y+3)^2+√2-y=0
则,x-y+3=0且2-y=0
解得x=-1 ,y=2
x+y=-1+2=1
(a+3)(a-1)+a(a-2)
=a²+2a-3+a²-2a
=2a²-3

(1)x=-1 y=2,x+y=1;
(2)展开得2a²-1

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