sin(π-α)-cos(π+α)=根号2/4(0
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sin(π-α)-cos(π+α)=根号2/4(0sin(π-α)-cos(π+α)=根号2/4(0sin(π-α)-cos(π+α)=根号2/4(0因为 sin(π-α)=sinα cos(π+α)
sin(π-α)-cos(π+α)=根号2/4(0
sin(π-α)-cos(π+α)=根号2/4(0
sin(π-α)-cos(π+α)=根号2/4(0
因为 sin(π-α)=sinα cos(π+α)=-cosα
所以原式=sinα+ cosα=根号二/4
则(sinα+ cosα)^2=1/8 即1+2sinαcosα=1/8
所以2sinαcosα=-7/8 由此得出2/π