求(xy+1)(yz+1)(xz+1)(x^2+1)(y^2+1)(z^2+1)已知(x-y)^2+(y-z)^2+(z-x)^2=(x+y-2z)^2+(z+x-2y)^2+(z+y-2x)^2,

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求(xy+1)(yz+1)(xz+1)(x^2+1)(y^2+1)(z^2+1)已知(x-y)^2+(y-z)^2+(z-x)^2=(x+y-2z)^2+(z+x-2y)^2+(z+y-2x)^2,求

求(xy+1)(yz+1)(xz+1)(x^2+1)(y^2+1)(z^2+1)已知(x-y)^2+(y-z)^2+(z-x)^2=(x+y-2z)^2+(z+x-2y)^2+(z+y-2x)^2,
求(xy+1)(yz+1)(xz+1)(x^2+1)(y^2+1)(z^2+1)
已知(x-y)^2+(y-z)^2+(z-x)^2=(x+y-2z)^2+(z+x-2y)^2+(z+y-2x)^2,

求(xy+1)(yz+1)(xz+1)(x^2+1)(y^2+1)(z^2+1)已知(x-y)^2+(y-z)^2+(z-x)^2=(x+y-2z)^2+(z+x-2y)^2+(z+y-2x)^2,
1

a

x+y=z

有已知条件得出: x=y=z