化简[x-(y-z)]-[(x-y)-z]A.2yB.2zC.-2yD.-2z
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化简[x-(y-z)]-[(x-y)-z]A.2yB.2zC.-2yD.-2z化简[x-(y-z)]-[(x-y)-z]A.2yB.2zC.-2yD.-2z化简[x-(y-z)]-[(x-y)-z]A
化简[x-(y-z)]-[(x-y)-z]A.2yB.2zC.-2yD.-2z
化简[x-(y-z)]-[(x-y)-z]
A.2y
B.2z
C.-2y
D.-2z
化简[x-(y-z)]-[(x-y)-z]A.2yB.2zC.-2yD.-2z
B.2z
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答
化简(x+Y)^2(y+z-x)(z+x-y)+(x-y)^2(x+y+z)(x+y-z)
化简:(2x-y-z)/(x-y)(x-z)+(2y-z-x)/(y-z)(y-x)+(2z-x-y)/(z-x)(z-y)化简:(2x-y-z)/(x-y)(x-z)+(2y-z-x)/(y-z)(y-x)+(2z-x-y)/(z-x)(z-y)我知道把分母化成一样的、但是之后怎么算?
化简(y-z)^2/(x-y)(x-z)+(z-x)^2/(y-x)(y-z)+(x-y)^2/(z-x)(z-y)
x-y/(z-x)(z-y) 一y-z/(x-y)(x-z) +z-x/(y-z)(y-x)
x^-(y-z)^/(x+y)^-z^
计算(x+y-z)(x-y-z)
计算:(x-y+z)(-x+y+z)
(x+y-z)(x-y+z)=
x y y ...y z x y ...y z z x ...y ........z z z ...x 求解行列式.
化简(x+y+z)^2-(x+y-z)^2
化简(x+y-z)((x-y+z)
化简(x-y+z)(x+y+z)
化简 (x+y+z)^2
化简(x+y+z)^2-(-x+y+z)^2+(x-y+z)^2-(x+y-z)^2
化简 (x+y+z)^2-(-x+y+z)^ 2+(x-y+z)^ 2-(x+y-z)^ 2
化简-(-3x-y+2z)-{-x+【4x-(x-y-z)-3x+2z}