已知4^m=8,16^n=6,求4^(2m-4n+1)

已知4^m=8,16^n=6,求4^(2m-4n+1)
已知4^m=8,16^n=6,求4^(2m-4n+1)

已知4^m=8,16^n=6,求4^(2m-4n+1)
4^(2m-4n+1)
=(4^2m)/(4^4n)*4
=4*(4^m)^2/(16^n)^2
=4*8^2/6^2
=64/9

4^(2m-4n+1)
=4^2m÷4^4n×4^1
=（4^m)^2÷（4^2n)^2×4
=8÷（16^n)2×4
=8÷6^2×4
=8÷36×4
=8/9

=(4^2m)*(1/(4^4n))*4
4^2m=(4^m)^2=8^2=64
4^4n=((4^2)^n)^2=(16^n)^2=6^2=36
所以，原式＝64*(1/36)*4=64/9

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