求y'

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求y''求y''求y''1.y=(3x+2)/(2x+3)y''=[(3x+2)''(2x+3)-(3x+2)(2x+3)'']/[(2x+3)^2]=[3(2x+3)-2(3x+2)]/[(2x+3)^2]=5

求y'
求y'

求y'
1.y=(3x+2)/(2x+3)
y'=[(3x+2)'(2x+3)-(3x+2)(2x+3)']/[(2x+3)^2]
=[3(2x+3)-2(3x+2)]/[(2x+3)^2]
=5/[(2x+3)^2]
2.y=sin(x^2+1)+(1-x)/√x
y'=2xcos(x^2+1)+[(1-x)'√x-(√x)'(1-x)]/x
=2xcos(x^2+1)+[-√x-(1-x)/(2√x)]/x
=2xcos(x^2+1)+[-√x-1/(2√x)+√x/2]/x
=2xcos(x^2+1)+(-√x/2x-√x/2x^2)
=2xcos(x^2+1)-√x/2x-√x/2x^2

1.y'=[3(2x+3)-2(3x+2)]/(2x+3)^2
=5/(2x+3)^2
2.y'=2xcos(x^2+1)+[-√x-(1-x)/2√x]/x