若x(y-1)-y(x-1)=4,求【(x²+y²)/2】-xy的值
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若x(y-1)-y(x-1)=4,求【(x²+y²)/2】-xy的值若x(y-1)-y(x-1)=4,求【(x²+y²)/2】-xy的值若x(y-1)-y(x-
若x(y-1)-y(x-1)=4,求【(x²+y²)/2】-xy的值
若x(y-1)-y(x-1)=4,求【(x²+y²)/2】-xy的值
若x(y-1)-y(x-1)=4,求【(x²+y²)/2】-xy的值
x(y-1)-y(x-1)=4
求得y-x=4
平方x²+y²=16+2xy
(x²+y²)/2-xy=8+xy-xy=8
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