用分解因式法解方程:(x-2)²-5(x-2)+4=0 (x-1)(x+3)=12用分解因式法解方程:(x-2)²-5(x-2)+4=0(x-1)(x+3)=12
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/18 12:54:18
用分解因式法解方程:(x-2)²-5(x-2)+4=0(x-1)(x+3)=12用分解因式法解方程:(x-2)²-5(x-2)+4=0(x-1)(x+3)=12用分解因式法解方程:
用分解因式法解方程:(x-2)²-5(x-2)+4=0 (x-1)(x+3)=12用分解因式法解方程:(x-2)²-5(x-2)+4=0(x-1)(x+3)=12
用分解因式法解方程:(x-2)²-5(x-2)+4=0 (x-1)(x+3)=12
用分解因式法解方程:(x-2)²-5(x-2)+4=0
(x-1)(x+3)=12
用分解因式法解方程:(x-2)²-5(x-2)+4=0 (x-1)(x+3)=12用分解因式法解方程:(x-2)²-5(x-2)+4=0(x-1)(x+3)=12
(x-2)²-5(x-2)+4=0
(x-2-1)(x-2-4)=0
x=3 x=6
(x-1)(x+3)=12
(x-1)(x-1+4)=12
(x-1)^2+4(x-1)-12=0
(x-1+6)(x-1-2)=0
x=-5 x=3
(x-2-4)(x-2-1)=0
x1=6,x2=3
x²+2x-3=12
x²+2x-15=0
(x-3)(x+5)=0
x1=3,x2=-5
(x-2-1)(x-2-4)=0