2x-y=1 3x+2y=5
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2x-y=13x+2y=52x-y=13x+2y=52x-y=13x+2y=5{2x-y=1(1){3x+2y=5(2)由1得,y=2x-1(3)把(3)代入(2)中,得3x+2(2x-1)=5x=1
2x-y=1 3x+2y=5
2x-y=1 3x+2y=5
2x-y=1 3x+2y=5
{2x-y=1 (1)
{3x+2y=5 ( 2)
由1得,y=2x-1 ( 3)
把(3)代入(2)中,得3x+2(2x-1)=5
x=1
把x=1代入(3)中,y=2×1-1=1
∴原方程组的解为{x=1
{y=1
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