高考三角函数 已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?(-2根号2/3)cos(π/12-α)=sin(5π/12+α )导出都会就是想问下最后答案为什么
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 13:54:06
高考三角函数已知cos(5π/12+α)=1/3,-π<α<-π/2,则cos(π/12-α)=?已知cos(5π/12+α)=1/3,-π<α<-π/2,则cos(π/12-α)=?(-2根号2/3
高考三角函数 已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?(-2根号2/3)cos(π/12-α)=sin(5π/12+α )导出都会就是想问下最后答案为什么
高考三角函数 已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?
已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?
(-2根号2/3)
cos(π/12-α)=sin(5π/12+α )
导出都会就是想问下最后答案为什么有符号 怎么看范围
高考三角函数 已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?已知cos(5π/12+α )=1/3 ,-π<α<-π/2,则cos(π/12-α)=?(-2根号2/3)cos(π/12-α)=sin(5π/12+α )导出都会就是想问下最后答案为什么
cos(π/12-α)
= sin(π/2-(π/12-α) )
=sin(5π/12+α )
因为-π<α<-π/2,
所以-7π/12