(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.

(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.
(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.

(x²+y²-z²+2xy）/(x²-y²+z²-2xz）计算.
具体过程是这样的：
原式=[(x²+2xy+y²）-z²]/[(x²-2xz+z²）-y²）]
=[(x+y)²-z²]/[(x-z)²-y²]
=(x+y+z)(x+y-z)/(x-z+y)(x-z-y)
=(x+y+z)/(x-z-y)

(x+y-z)/(x-y+z)

(x+y)^2-Z^2/(x+z)^2-y^2=(x+y+z)(x+y-z)/(x-y+z)(x+y+z)=x+y-z/x-y+z

H

看看我的截图