y+10=6(x+10),y-10=2(x-10)(用二元一次方程)要求有过程

x,y 满足x(x-2)-y(y-6)=-10,求x,y的值 x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以（x^2+y^2/y)^2的值 (x+y)/6+(x-y)/10=1,(x+y)/6-(x-y)/10=5 {6/x+y+10/x-y=30 6/x+y-10/x-y=-1 求f(x,y)=x+y+7的最大值,使(x,y)满足x+2y≤10,2x+y≥6,y≥0 解方程组 10（x-y)=3(x+y)+15 6(x+y)=4(2x-y)+1610（x-y)=3(x+y)+156(x+y)=4(2x-y)+16 解方程组 10（x-y)=3(x+y)+15 6(x+y)=4(2x-y)+1610（x-y)=3(x+y)+156(x+y)=4(2x-y)+16分开的。 2/x-y + 6/x+y = 11/10 分式方程组 4/x-y - 6/x+y =1/10 3(2X+Y)+(2(2x-Y)=6 (8X+4y)-(10X-5Y)=2 已知x,y满足约束条件 2x+5y>=10 2x-3y>=-6 2x+y 已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y 已知x^2+y^2--6x--2y+10=0,求x+y/x--y 已知x^2+y^2+6x-2y+10=0,求x+y/x-y的值谢谢 已知实数x,y满足2x+5y>=10;2x-3y>-6;2x+y 已知x^2-2x+y^2+6y+10=0,求分式x-y/x+y的值 已知：4x^2+y^2-4x-6y+10=0,求y/x-x/y的值 已知x、y满足：x^2+y^2+6x-10y+34=0,求y-x的值 若x^2+y^2-10x-6y+34=0,求（x-y)/(x+y)的值