已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为

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已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为5x+xy-5

已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为
已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为

已知x/1-y/1=3,则5x+xy-5y/x+2y-y的值为
5x+xy-5y/x+2y-y?应该是：(5x+xy-5y)/(x+2xy-y) 吧!
解析：
已知x分之1 - y分之1=3,那么：
(xy)分之(y-x)=3
即y-x=3xy
所以：(5x+xy-5y)/(x+2xy-y)
=[5(x-y)+xy]/(x-y+2xy)
=(-15xy+xy)/(-3xy+2xy)
=(-14xy)/(-xy)
=14/1
（注：不确定上式哪个是分子,哪个是分母,所以由楼主自行判别了）

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