求方程5x²+6xy+2y²-4x+2y+1=0的实数根

求方程5x²+6xy+2y²-4x+2y+1=0的实数根
求方程5x²+6xy+2y²-4x+2y+1=0的实数根

求方程5x²+6xy+2y²-4x+2y+1=0的实数根
（9x²+6xy+y²)-(4²x+4x+1)+(y²+2y+1)+1=0
(3x+y)²-(2x+1)²+(y+1)²+1=0
(3x+y)²+1+(y+1)²=(2x+1)²
(2x+1)²=1
x=-1
(3x+y)²+(y+1)²=0
y1=3 y2=-1
我的答案正确为啥不选.

还少条件吧 这怎么解

00

题目错误：
5x²-6xy+2y²-4x+2y+1=0
4x²-4xy+y²-2(2x-y)-2xy+y²+x²+1=0
(2x-y)²-2(2x-y)+1-2xy+y²+x²=0
(2x-y-1)²+(x-y)²=0
2x-y-1=0且x=y(或2x-y+1=0,
x=1,y=1