a12－a22＋a32-a42…的前2n项和

在等差数列{an}中,已知公差d＝5,前20项的和S20＝400,则(a22＋a42＋…＋a202)－在等差数列{an}中,已知公差d＝5,前20项的和S20＝400,则(a22＋a42＋…＋a202

n^2(n>=4)正数列排成n行,其中每一行的数成等差数列,每一列数成等比数列,并且所有公比相等a11,a12,a13,a14,a15a21,a22,a23,a24,a25a31,a32,a33,a3

高中文科数学6.等比数列｛an｝,已知对于任意的自然数n,a1+a2+a3+…+an=2n-1,则a12+a22+a32+…+an2等于高中文科数学6.等比数列｛an｝,已知对于任意的自然数n,a1+

等比数列(1617:53:34)已知数列an前n项和Sn=2n-1,求a12+a22+……+an2 等比数列(1617:53:34)已知数列an前n项和Sn=2n-1,求a12+a22+……

1.条件a11a12a13a21a22a23=2a31a32a33计算a11a12a1310a2110a2210a23A31a32a33的值=1.条件a11a12a13a21a22a23=2a31a3

求教2道简单的线性代数题目1.写出4阶段行列式：a11a12a13a14a21a22a23a24a31a32a33a34a41a42a43a44中一切带负号且含元素a23的项2.用定义计算行列式：a0

线性代数计算题求解用定义计算下列行列式010……0002……0......000……n-1n00……0第二题a11a12a13a14a15a21a22a23a24a25a31a32000a41a420

四阶行列式的展开三阶行列式D=|a11a12a13||a21a22a23||a31a32a33|它展开则是：a11a22a33+a12a23a31+a13a21a32-a11a23a32-a12a21

四阶行列式死算公式三阶a11a12a13a21a22a23a31a32a33=a11a22a33+a12a23a31+a13a21a32-a13a22a31-a12a21a33-a11a23a32那么

数列(1716:56:38)若等比数列｛an｝满足：a1+a2+a3+a4+a5=3,a12+a22+a32+a42+a52=12,则a1-a2+a3-a4+a5的值是：  数列(

用行列式的定义计算下列行列式a11a12a13a14a15a21a22a23a24a25a31a32000a41a42000a51a52000用行列式的定义计算下列行列式a11a12a13a14a15

有行列式的定义证明a11a12a13a14a15a21a22a23a24a25a31a32000=0a41a42000a51a52000有行列式的定义证明a11a12a13a14a15a21a22a2

已知3阶行列式a11a12a13,a21a22a23,a31a32a33=2,算a11a12a13,10a2110a2210a23,a31a32a33的值1-2-1已知3阶行列式a11a12a13,a

1.二阶行列式|R-12|≠0.那么R应该满足什么条件?|2R-1|2.如果行列式D=|a11a12a13|=M≠0D1=|2a112a122a13||a21a22a23||2a212a222a23|

用范德蒙德行列式计算（1）abca2b2c2b+cc+aa+b(2)11111+a11+a21+a31+a4a1+a12a2+a22a3+a32a4+a42a12+a13a22+a23a32+a33a

写出四阶行列式种含有因子a11a23的项a11a12a13a14a21a22a23a24a31a32a33a34a41a42a43a44看了很多解答说是把a11拿走计算剩下的三阶行列式,我想问一下这是

设矩阵A,则齐次线性方程组AX=0包含的基础解系的个数为?矩阵A为a11=a12=a13=a14=1,a21=2,a22=4,a23=3,a24=1,a31=3,a32=5,a33=2.a34=4,a

矩阵(a11a12a21a22a31a32)向量组线性矩阵A=(a11a12a21a22a31a32)的行向量组线性矩阵(a11a12a21a22a31a32)向量组线性矩阵A=(a11a12a21a

行列式|a11a12a13,a21a22a23,a31a32a33|=2,则3a113a123a13-3a21-3a22-3a23a31a32a33行列式|a11a12a13,a21a22a23,a3

用VB编程：做一个倒起的直角三角形a11a21a22a31a32a33a41a42a43a44把它倒成这个a11a21a31a41a22a32a42a33a43a44用VB编程：做一个倒起的直角三角形