设f(x)在[a,b]上二阶可导

设f(x)在[a,b]上二阶可导,且f''''(x)>0,证明:函数F(x)=(f(x)-f(a))/(x-a)在(a,b]上单调增加设f(x)在[a,b]上二阶可导,且f''''(x)>0,证明:函数F(x

设f(x)在[a,b]二阶可导,且f''''(x)设f(x)在[a,b]二阶可导,且f''''(x)设f(x)在[a,b]二阶可导,且f''''(x)这也就是所谓的Hadamard不等式得一边,条件是f是凸函数，

设f在[a,b]上可导,|f''(x)|设f在[a,b]上可导,|f''(x)|设f在[a,b]上可导,|f''(x)|令F(x)=∫(a,x)f(t)dt,则知F可导且F''(x)=f(x),且F(a)=F

设f(x)在[a,b]上连续,且a设f(x)在[a,b]上连续,且a设f(x)在[a,b]上连续,且af(x)在闭区间[a,b]上必有最大值和最小值,设为A与B,则mB+nB

设函数f(x)在[a,b]上连续,a设函数f(x)在[a,b]上连续,a设函数f(x)在[a,b]上连续,a根据闭区间上连续函数的中间值定理,闭区间上连续函数一定能取到最大值和最小值之间的任何一个值,

设f(x)在[a,b]上连续,且a设f(x)在[a,b]上连续,且a设f(x)在[a,b]上连续,且a[a,b]上连续,由极值大A,Bb

设函数f(x)在【a,b】a设函数f(x)在【a,b】a设函数f(x)在【a,b】a望采纳令F(x)=∫a~xf(t)dt,F''(x)=f(x)因为F(a)=∫a~af(t)dt=0，F(b)=)=∫

设f(x)在[a,b]上连续,且a设f(x)在[a,b]上连续,且a设f(x)在[a,b]上连续,且a本题是对于任何正整数p,q,否则有问题.构造函数g(x)=pf(c)+qf(d)-(p+q)f(x

设f(x)在[a,b]上连续,a设f(x)在[a,b]上连续,a设f(x)在[a,b]上连续,a证明：令k=[pf(c)+qf(d)]/(p+q)无妨设f(c)≤f(d),由于q是正数,所以qf(c)

设函数f(x)在[a,b]上连续,a设函数f(x)在[a,b]上连续,a设函数f(x)在[a,b]上连续,a因为f(x)在[a,b]上连续,则f(x)在[x1,xn]上连续.因为闭区间内的连续函数,必

设函数f(x)在[a,b]上连续,在(a,b)内可导且f''(x)设函数f(x)在[a,b]上连续,在(a,b)内可导且f''(x)设函数f(x)在[a,b]上连续,在(a,b)内可导且f''(x)F''(x

设函数f(x)在[a,b]上连续,在(a,b)上可导且f''(x)设函数f(x)在[a,b]上连续,在(a,b)上可导且f''(x)设函数f(x)在[a,b]上连续,在(a,b)上可导且f''(x)

设F(X)在a设F(X)在a设F(X)在af(x)=k(x-x1)(x-x2)g(x)=f(x)+f''(x)=k(x-x1)(x-x2)+k(2x-x1-x2)g(x1)g(x2)结论是不是应该是f(

设函数f(x)在区间(a,b)内恒满足,|f(x)-f(y)|设函数f(x)在区间(a,b)内恒满足,|f(x)-f(y)|设函数f(x)在区间(a,b)内恒满足,|f(x)-f(y)||[f(x)-

设f(x)在(a,b)恒满足|f(x)-f(y)|设f(x)在(a,b)恒满足|f(x)-f(y)|设f(x)在(a,b)恒满足|f(x)-f(y)|因为：2|x－y|²的最小值是0,且函数

设函数f(x),g(x)在[a,b]上均可导,且f''(x)设函数f(x),g(x)在[a,b]上均可导,且f''(x)设函数f(x),g(x)在[a,b]上均可导,且f''(x)f''(x)

设函数f(x),g(x)在区间[a,b]上连续,且f(a)设函数f(x),g(x)在区间[a,b]上连续,且f(a)设函数f(x),g(x)在区间[a,b]上连续,且f(a)题目出错了,比如令a=0,

设f(x)在[a,b]二阶可导,f''(x)>0,f''''(x)>0,证明：(b-a)f(a)b)f(x)dx设f(x)在[a,b]二阶可导,f''(x)>0,f''''(x)>0,证明：(b-a)f(a)b)

设f(x)在[a,b]上二阶可导,且f(a)=f(b)=0,f''(a)*f''(b)>0,试证存在ξ,η属于（a,b）,使f(ξ)=0及f''''(η)=0设f(x)在[a,b]上二阶可导,且f(a)=f(

【50分高数微积分题】设f(x)在[a,b]上连续,在（a,b）内可导f(a)f(b)>0f(a)f[(a+b)/2]【50分高数微积分题】设f(x)在[a,b]上连续,在（a,b）内可导f(a)f(