已知数列{an}的前n项和为Sn,且满足an+2Sn·Sn-1=0
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/21 20:50:25
已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证:{1/Sn}是等差数列已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证:{
已知数列{an}a1=2前n项和为Sn且满足SnSn-1=3an求数列{an}的通项公式an已知数列{an}a1=2前n项和为Sn且满足Sn+Sn-1=3an求数列{an}的通项公式an已知数列{an
已知数列{an}的前n项和为Sn,且满足Sn=2an-1(n属于正整数),求数列{an}的通项公式an已知数列{an}的前n项和为Sn,且满足Sn=2an-1(n属于正整数),求数列{an}的通项公式
已知数列{an}的前n项和为Sn,且满足an+2Sn·Sn-1=0(n大于等于2),a1=1/2,求证:{1/Sn}是等差数列.已知数列{an}的前n项和为Sn,且满足an+2Sn·Sn-1=0(n大
已知数列{an}中,an>0,前n项和为Sn,且满足Sn=1/8(an+2)^2.求证数列{an}是等差数列.已知数列{an}中,an>0,前n项和为Sn,且满足Sn=1/8(an+2)^2.求证数列
已知数列{an}的前n项和为Sn,且满足Sn=2an-1,n为正整数,求数列{an}的通项公式anRT,已知数列{an}的前n项和为Sn,且满足Sn=2an-1,n为正整数,求数列{an}的通项公式a
已知正项数列{an}的前n项和为sn,且满足sn+sn-1=kan^2+2求an已知正项数列{an}的前n项和为sn,且满足sn+sn-1=kan^2+2求an已知正项数列{an}的前n项和为sn,且
已知数列{an}的前n项和为Sn,且an=Sn·Sn-1(n大于等于2,Sn不为0),a1=2/91、求证{1/Sn}为等差数列2、求满足an>an-1的自然数n的集合求详解,特别是第二问,为什么1/
已知数列{an}的前n项和Sn满足Sn=2/3an-1/3,且1已知数列{an}的前n项和Sn满足Sn=2/3an-1/3,且1已知数列{an}的前n项和Sn满足Sn=2/3an-1/3,且1由题意得
已知数列An的前n项和为Sn.且满足an+2Sn*Sn-1=0=2>,a1=1/2,求证1/Sn是等差数列,求通项an的表达试已知数列An的前n项和为Sn.且满足an+2Sn*Sn-1=0=2>,a1
已知数列{an}的前n项和为sn,且满足sn=n已知数列{an}的前n项和为sn,且满足sn=n已知数列{an}的前n项和为sn,且满足sn=nan=Sn-S(n-1)=1说明是常数列啊an=1常数列
已知数列an前n项的和为Sn且满足Sn=1-nann=自然数已知数列an前n项的和为Sn且满足Sn=1-nann=自然数已知数列an前n项的和为Sn且满足Sn=1-nann=自然数在式中令n=1得a1
已知数列{an}的前n项和为sn,且满足a1=1/2,an+2snsn-1=0(n≥2)(1)问:数列{1/Sn}是否为等差数列?(2)求Sn和an已知数列{an}的前n项和为sn,且满足a1=1/2
已知数列{an}中,an>0,Sn为{an}的前n项和,且an+1/an=2Sn,求an.已知数列{an}中,an>0,Sn为{an}的前n项和,且an+1/an=2Sn,求an.已知数列{an}中,
已知数列{an}中,an>0,Sn为{an}的前n项和,且an+1/an=2Sn,求an.已知数列{an}中,an>0,Sn为{an}的前n项和,且an+1/an=2Sn,求an.已知数列{an}中,
已知数列{an}的前n项和为Sn,且满足Sn=3/2(an-1)(n∈正整数)求an的通项公式已知数列{an}的前n项和为Sn,且满足Sn=3/2(an-1)(n∈正整数)求an的通项公式已知数列{a
已知正数数列{an}的前n项和为Sn,且对于任意正整数n满足2根号Sn=an+1求an通项已知正数数列{an}的前n项和为Sn,且对于任意正整数n满足2根号Sn=an+1求an通项已知正数数列{an}
已知正数数列{an}的前n项和为Sn,且对于任意正整数n满足2根号Sn=an+1求an通项已知正数数列{an}的前n项和为Sn,且对于任意正整数n满足2根号Sn=an+1求an通项已知正数数列{an}
已知正数数列{an}的前n项和为Sn,且对于任意正整数n满足2根号Sn=an+1求an通项已知正数数列{an}的前n项和为Sn,且对于任意正整数n满足2根号Sn=an+1求an通项已知正数数列{an}
(1)已知数列an的前n项和为sn满足sn=an²+bn,求证an是等差数列(2)已知等差数列an的前n项和为sn,求证数列sn/n也成等差数列(1)已知数列an的前n项和为sn满足sn=a